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2016石家庄二模

2017-01-07 06:19:46 来源网站:百味书屋

篇一:石家庄2016年二模数学答案

2016年石家庄市初中毕业生升学文化课一模考试

数学试题参考答案及评分标准

说明:

1.各地在阅卷过程中,如考生还有其它正确解法,可参照评分标准按步骤酌情给分. 2.坚持每题评阅到底的原则,当考生的解答在某一步出现错误,影响了后继部分时,如果该步以后的解答未改变这一题的内容和难度,可视影响的程度决定后面部分的给分,但不得超过后继部分应给分数的一半;如果这一步后面的解答有较严重的错误,就不给分.

3.解答右端所注分数,表示正确做到这一步应得的累加分数.只给整数分数. 一、选择题(1~10小题,每小题3分;11~16小题,每小题3分,共42分)

二、填空题(每小题3分,共12分) 17. 2(x+2)(x-2) ; 18. 1,

2;

3 ; 19. 503三、解答题(本大题共6个小题,共66分)

21.

(1)解:

2

?=(-2)-4?1?(m??4?4m

因为方程有两个相等的实数根,所以??0,即4?4m?0 解得:m?

1

......................................... ............................... ............................4分 (2).解:

m?12m?1

?(m?)mm

m?1m2?2m?1??()mmm?1m??m(m?1)21?

m?1 ................................. .......................................8分

1??当m?1时,

m?1......................................... ............................... ..........................10分

数学试题参考答案1 第 页 (共 4 页)

22. (1)证明:由于四边形ABCD是菱形,则有∠A=∠C,AD=BC.连接BP,

由作图过程可知BD=BP,DC′=PC,BC=BC′, 则△BDC′≌△BPC(SSS). ∴∠C=∠C′,BC=BC′.

∴∠A=∠C′,AD=B C′. ......................................... ................................................8分 (2)假. ............................................. ................................................10分 23.解:(1)38;6. .............................................. ................................................4分

(2)60;图略. ................. .................................. .........................................7分

(3)72. ................. .................................. ............................ .........10分24.解:(1)由图象得当﹣4<x<﹣1时,一次函数大于反比例函数值;....................2分 (2)设一次函数的解析式为y?kx?b,

y?kx?b的图象过点(﹣4,),(﹣1,2),则

1?

k???k?b?2???2

,解得 ??1

5?4k?b??b???2??2

所以一次函数的解析式为y?反比例函数y?

15

x?, 22

m

图象过点(﹣1,2), x

m=﹣1×2=﹣2;................................... .......................................7分 (3)连接PC、PD,如图, 设P(x,x+)

由△PCA和△PDB面积相等得

(x+4)=

解得:x=﹣, 所以y=x+

=,

∴P点坐标是(﹣,). ..................................................................... 11分

25.解:(1)当x?20时,

|﹣1|×(2﹣x﹣),

数学试题参考答案2 第 页 (共 4 页)

y =-10×20+500=300, 300×(12-10)=300×2=600,

即政府这个月为他承担的总差价为600元.............................................................2分 (2)依题意得,w?(x?10)(?10x?500) ??10x2?600x?5000 ??10(x?30)2?4000

∵a??10<0,∴当x?30时,w有最大值4000.

即当销售单价定为30元时,每月可获得最大利润4000.

..................................................................... 5分 (3)由题意得:?10x2?600x?5000?3000, 解得:x1?20,x2?40.

∵a??10<0,抛物线开口向下,

∴结合图象可知:当20≤x≤40时,w≥3000.

又∵x≤25,

∴当20≤x≤25时,w≥3000. .....................................................................8分 设政府每个月为他承担的总差价为p元,

∴p?(12?10)?(?10x?500)

0 ??20x?100.

∵k??20<0,∴p随x的增大而减小, (第25题)

∴当x?25时,p有最小值500.

即销售单价定为25元时,政府每个月为他承担的总差价最少为500元..................................11分

26.

解:发现

(1) 9-6;. ................................. ............................. ............ .................................2分 (2) MN所在直线经过原点............ ............................. ............ .................................3分 理由:当t=9时,∠APN=180o-9×15o=45o,AP=9×1=9, 设此时直线MN交y轴于点D, 则AD=AP·tan45o=9×1=9, 又OA=9,

所以点D与点O重合,即MN所在直线经过原点... ............ ................................5分 (3)如图1,

当点P在直线l上时,过点P作PH⊥x轴,垂足为H. OQ=OH+QH=AP+CQ=t,

由OQ+CQ

=t+t=OC

=22+t=11.

此时,∠APN=180o-11×15o=15o, ∠NPQ=180o-15o-60o=105o, ∠MPQ=180o-105o=75o.

则S左:S右=105:75=7:5............................8分 拓展

如图2,设直线l与AB交于点E,与半圆P相切于点T.

数学试题参考答案3 第 页 (共 4 页)

PH

= t

=t,?

tan60

则PT

=PE=

PT,AE=AP+PE=t+6.

sin60?

过点E作EF⊥x轴,垂足为F. 则OQ=OF+FQ=AE+CQ=t,

由OQ+CQ

=6+t+t=OC

=22+t=8.

此时,点P的坐标为(8,9)... ...........................12分 探究

当半圆P在直线右侧,且与直线l相切时,如图3所示. 设直线l与AB交于点G,与半圆P相切于点R. 则PR

=PG=

EF

=(t+6)

t, ?

tan60

PR,AG=AP-PG=t-6.

sin60?

过点G作GJ⊥x轴,垂足为J, 则OQ=OJ+JQ=AG+CQ=t,

由OQ+CQ

=t+t=OC

=22+t=14.

则直线l与半圆P有公共点的时间为14-8=6秒.. ...........................14分

GJ

= (t-6)

t, ?

tan60

数学试题参考答案4 第 页 (共 4 页)

篇二:石家庄市2016届高中毕业班二模英语试题参考答案

2016届石家庄市高中毕业班第二次模拟考试试题

英语

参考答案

听力(20×1.5=30):1—5 ABACC 6—10 ABBCB 11—15 CABAB 16—20 CABCC 阅读理解(15×2=30):21—23 DBA24—27 ABCC28—31 CBAD32—35 BCDC

七选五阅读填空(5×2=10): 36—40 FBCGE

完形填空(20×1.5=30): 41—45 BCADB 46—50 CDABD 51—55 ADBCB 56—60 ACDBA 语法填空(10×1.5=15): 61. to finish 62. done63. Inventions 64. noisy65. a

66. what67. spent 68. physically 69. his 70. who/that 短文改错(10×1=10):openedwhich

to help students to communicate better and improve your English. The blog serves as /\ open platforman

havepossiblyyourattracted

you are free to get involved in the weekly discussion.

beneficial is

to visit it.

书面表达(满分25分):

参考范文

Dear Jason,

I’m Li Hua. I’m writing to ask you to do me a favor. It’s about an English speech contest with the title An Unforgettable Experience in High School, which I’m going to take part in this Saturday. I’ve finished my draft, but I find it still far from satisfactory.

I’m not sure of the usage of some words. There may also be some mistakes in grammar and sentence structures. Would you be so kind to spare some time to check them out and improve my article? If it’s convenient to you, please send it back by Thursday afternoon.

I’d appreciate it if you could give me your guidance. Looking forward to your reply. (113 words) Yours,

Li Hua

注:请各校阅卷教师认真学习本次书面表达的评分细则。

书面表达评分细则

1、本题总分为25分,按5个档次给分。

2、评分时,先根据文章的内容、语言与结构初步确定其所属档次,然后以该档次的要求来衡量,确定或

调整档次,最后给分。

3、词数少于80和多于120的,从总分中减去2分。

4、评分时,应注意的主要内容为:内容要点、应用词汇和语法结构的数量和准确性及上下文的连贯性、根据表达内容的层次适当分段及语言的得体性。

5、拼写与标点符号是语言准确性的一个方面,评分时,应视其对交际的影响程度予以考虑。英、美拼写及词汇用法均可接受。

6、如书写较差,以至影响交际,将分数降低一个档次。

7、本次书面表达难度预设为0.6,预设平均分为15分。

8、书面表达要点认定:

要点1. 自我介绍

要点2. 寻求帮助

要点3. 求助内容

要点4. 回复时间

要点5. 表达感谢

各档次的给分范围和要求

第五档 (21-25分)

完全完成了试题规定的任务。

—覆盖所有内容要点。

—应用了较多的语法结构和词汇。

—语法结构或词汇方面有些许错误,但为尽力使用较复杂结构或较高级词汇所致;具备较强的语言运用能力。

—有效地使用了语句间的连接成分,使全文结构紧凑。

完全达到了预期的写作目的。

第四档 (16-20分)

完全完成了试题规定的任务。

—虽漏掉1、2个次重点,但覆盖所有主要内容。

—应用的语法结构和词汇能满足任务的要求。

—语法结构或词汇方面应用基本准确,些许错误主要是因尝试较复杂语法结构或词汇所致。

—应用简单的语句间的连接成分,使全文结构紧凑。

达到了预期的写作目的。

第三档 (11-15分)

基本完成了试题规定的任务。

—虽漏掉一些内容,但覆盖所有主要内容。

—应用的语法结构和词汇能满足任务的要求。

—有一些语法结构或词汇方面的错误,但不影响理解。

—应用简单的语句间的连接成分,使全文内容连贯。

整体而言,基本达到了预期的写作目的。

第二档 (6-10分)

未恰当完成试题规定的任务。

—漏掉或未描述清楚一些主要内容,写了一些无关内容。

—语法结构单调、词汇项目有限。

—有一些语法结构或词汇方面的错误,影响了对写作内容的理解。

—较少使用语句间的连接成分,内容缺少连贯性。

信息未能清楚地传达给读者。

第一档 (1-5分)

未完成试题规定的任务。

—明显遗漏主要内容,写了一些无关内容,原因可能是未理解试题要求。

—语法结构单调、词汇项目有限。

—较多语法结构或词汇方面的错误,影响对写作内容的理解。

—缺乏语句间的连接成分,内容不连贯。

信息未能传达给读者。

未能传达给读者任何信息:内容太少,无法评判;写的内容均与所要求内容无关或所写内容无法看清。 附:听力材料

听力原文:

(Text 1)

W: Hello. I’d like to reserve a table for tonight at eight o’clock.

M: Certainly ma’am. And for how many people? The largest table left seats six.

W: Oh, right. A party of five.

(Text 2)

M: Well, I have studied computer programming for four years in college.

W: But I don’t seem to see any background in terms of work on your application.

M: But I’m confident I can do the job well.

(Text 3)

W: Pass me the potatoes again, please. Oh, let me have some more chicken.

M: Don’t you think you’re eating too much?

W: I promise, I’ll just eat a little more.

(Text 4)

M: Our basketball team is playing in the finals in the stadium this Sunday but I don’t have a ticket. I guess I’ll just watch it on TV.

W: Actually I have a ticket. But I’m not feeling well. You can have it.

M: That’s very nice of you.

(Text 5)

W: It seems Jackie still hasn’t received the plan.

M: Really? I sent it to him last week.

W: Anyway, I will bring it to him in person today. Would you call him to let him know I’ll be coming by? M: OK.

(Text 6)

M: Are you ready to go? We need to leave soon.

W: Not yet. I’m looking for my red shoes.

M: The ones I bought for you last week?

W: Yes, I want to wear them to the movies tonight.

M: I think they should be in the bedroom.

W: I just looked in there and I didn’t see them.

M: Did you look under the sofa?

W: No, why would they be under the sofa?

M: The cat likes them more than you do. And he likes to take things there.

(Text 7)

M: Would you like to have lunch with me today, Maria? I’m going to try the new Greek place that just opened downtown.

W: You’re talking about Green Star, the one across from City Hall? I went there with some friends yesterday. It isn’t as enjoyable as it is advertised. It’s a bit noisy and I couldn’t feel relaxed. I wrote a review last night on

the Internet about it.

M: Oh. I never pay attention to reviews on the Internet or in the paper. Anyway, now I’m still going to try it myself.

(Text 8)

W: Have you finished your project?

M: Well, actually, I am running a little behind. It’s 40% done.

W: What’s the problem?

M: I never talk to my co-workers when I have problems. They are always too busy to help a new staff member like me.

W: Have you ever helped other people when they are in trouble?

M: Well, nobody ever asks me for help.

W: I think you should communicate with them more. A team makes things better, you know.

M: I see your point, but…

W: Come on! Just pay more attention to your co-workers. I am speaking from experience.

M: Thank you so much. I will try.

W: If you have any other problems with your work, let me know.

M: Thanks very much. I promise I will work harder.

(Text 9)

W: Good evening and welcome to tonight’s edition of Legendary Lives. Our subject this evening is James Dean. Edward Murray is the author of a new biography of Dean. So Edward, tell us what you know about Dean’s early life.

M: He was born in Indiana in 1931, but his parents moved to California when he was five. He wasn’t there long though because his mother passed away just four years later. Dean’s father sent him back to Indiana after that to live with his aunt.

W: So how did he get into acting?

M: Well, first he acted in plays at high school, then he went to college in California where he got into acting officially. In 1951 he moved to New York to do more stage acting.

W: Then when did he start movies?

M: In 1955. His first starring role was in East of Eden. The movie that really made him famous was Rebel Without a Cause. That was about teenagers who felt like they didn’t fit into society. Dean died in a car crash in California.

(Text 10)

M: Welcome to Haybridge Hall. I’d like to introduce the general history of the house to you.

Haybridge Hall was constructed at the end of the 15th century and was originally called Hawken Hall after the first family who owned it. The Hawken family sold it and the name Haybridge was used by the family who bought it. The Yardley family owned Haybridge for some 200 years and turned the surrounding area into farmland. The Yardley family left Haybridge in 1722 and the place was left empty for about sixty years.

The famous local author William Hoaten bought Haybridge in 1784. The Hoaten family stayed at Haybridge until the beginning of the Second World War when the British Army took it over. After the war, the Hoaten family decided it would be too costly to move back into Haybridge Hall and so Haybridge came to be owned by English Heritage. English Heritage made a big repair operation in the 1970’s. Haybridge Hall remains to this day one of the finest examples of British architecture and the furnishing within gives a good idea of what country life was like three to four centuries ago in this country.

That’s all from me. Now you can walk around Haybridge Hall.

篇三:2016年石家庄市第二次模拟考试试题答案数学理科

2016年石家庄市第二次模拟考试试题答案(数学理科)

一、选择题1-5 BAACB 6-10CABBA 11-12CC

414. 240 15. -6 16. 1或9 5abc???2R可得:三、解答题17.(I)由正弦定理sinAsinBsinC

2RsinA=3?2RsinBcosC…………………1分 二、填空题13.

?A?B?C???sinA?sin(B?C)=3sinBcosC, -----3分即sinBcosC?cosBsinC=3sinBcosC

cosBsiCntanC?cosBsinC=2sinBcosC?=2故=2. -------------------------5分 sinBcosCtanB

(II)(法一)由A?B?C??,得tan(B?C)?tan(??A)??3, 即tanB?tanC3tBan??3, 将tanC?2tanB代入得:??3,1?tanB?tanC1?22tBan

1tanB??或-------------------------7分 B?解得tan1tanB同正,所以,根据tanC?2tanB得tanC、2

tanB?1,tanC?2. ………8分

则tanA?

3,可得sinB? sinC?sinA?,

?b?,……10分 所

以代入正弦定理可

115S?ABC?absiCn???-------123分 22(法二)由A?B?C??得 tan(B?C)?tan(??A)??3, 即tanB?tanC3tBan??3, 将tanC?2tanB代入得:??3,21?tanB?tanC1?2tBan

1tanB??或-------------------------7分 B?解得tan1tanB同正,所以,根据tanC?2tanB得tanC、2

tanB?1,tanC?2.………8分

又因为a?3bcosC?3,所以bcosC?1,?abcosC?3

11?abcosCtanC?6. --------------10分 ?S?ABC?absinC??6?3. ---------------1222


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    石家庄2016年二模数学答案2016年石家庄市初中毕业生升学文化课一模考试数学试题参考答案及评分标准说明:1.各地在阅卷过程中,如考生还有其它正确解法,可参照评分标准按步骤酌情...

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